The magnetic field at the centre O due to the current element I d l is. If these moving charges are in a wirethat is, if the wire is carrying a currentthe wire should also experience a force. Gauss Law Review Remember the idea of the surface integral? Amperes Law Direction = u 0 I Use the right hand rule: Point curled fingers in direction of integration (your choice, usually!). By clicking Post Your Answer, you agree to our terms of service, privacy policy and cookie policy. Torque on current-carrying loop in a magnetic field. I used $dl$ as the element of current carrying wire not the Amperean loop. Prepare here for CBSE, ICSE, STATE BOARDS, IIT-JEE, NEET, UPSC-CSE, and many other competitive exams with Indias best educators. The wire has a radius of near zero meters. This force can easily be large enough to move the wire, since typical currents consist of very large numbers of moving charges. Registration confirmation will be emailed to you. EDIT: Following @Dale answer, we can do something like this r =. Is it an experimental fact? A wire carrying electric current will produce a magnetic field with closed field lines surrounding the wire. magnetic field due to straight current-carrying conductor, # magnetic field due to straight current carrying conductor, Lenzs Law of Electromagnetic Induction: Definition & Formula. By combining the . Creating Local Server From Public Address Professional Gaming Can Build Career CSS Properties You Should Know The Psychology Price How Design for Printing Key Expect Future. Magnetic Field Produced by a Current-Carrying Solenoid A solenoid is a long coil of wire (with many turns or loops, as opposed to a flat loop). So it is okay that it creates a magnetic field around itself, but my interest is in knowing how we can calculate the strength of this magnetic field. Now, the problem is how do we know that the magnitude of B is going to be constant and its direction will be the same as a line element. My work as a freelance was used in a scientific paper, should I be included as an author? Take the wire and break it into pieces. Magnetic field due to current carrying wire derivation 1 See answer Mdamaan1357 is waiting for your help. Magnetic Field Due To A Long Straight Wire Derivation. (b) Write the formula to find the magnetic field due to a long straight current carrying wire i.e. Note axes in 10 -2 m Problem solving tip: u 0/4 = 1 x 10 -7 Tm/A, Answer: Numerical Problem Sin and RH rule method What are the magnetic field strength and direction at the dot in the figure? We just substitute in this equation. The best answers are voted up and rise to the top, Start here for a quick overview of the site, Detailed answers to any questions you might have, Discuss the workings and policies of this site, Learn more about Stack Overflow the company, $$ \oint \mathbf{B} \cdot d\mathbf{l} = \mu_{0} ~I$$, $$ d\mathbf{B} = \mu_0 /4\pi ~ I ~ \frac {d\mathbf{l} \times \mathbf{r}} {r^3} $$, $ \mathbf{r} = (rcos\theta, rsin\theta , z) $, $$ d\mathbf{l} \times \mathbf{r} = -z ~dl \hat j + rsin\theta \hat k$$, $$ dB = \mu_0/4\pi ~I~ |d\mathbf{l} \times \mathbf{r}| /r^3 = \mu_0/4\pi ~I ~ \sqrt{z^2+r^2sin^2\theta} dl/ r^3 $$. Since there is cylindrical symmetry (axisymmetric) the magnitude can only depend on $r$, and therefore cannot depend on $\theta$ or on $z$. Right-hand rule for a current-carrying wire in a magnetic field B When a wire carrying an electric current is placed in a magnetic field, each of the moving charges, which comprise the current, experiences the Lorentz force, and together they can create a macroscopic force on the wire (sometimes called the Laplace force). chem. A 0.1 m long conductor carrying a current of 50 A is perpendicular to a magnetic field of 1.25 mT Magnetic field at the axis of Circular Loop, Solved Examples on Magnetic field due to circular loop, Amperes Circuital Law & its Applications, Magnetic field on the axis of a long solenoid, Motion of charged particle in a magnetic field, Deviation of charged particle in uniform magnetic field & Cyclotron, Force on a current carrying wire in a magnetic field, Force between two parallel current carrying wires, Torque on a current carrying loop in a uniform magnetic field. Numerical Problem # 14: Superposition of magnetic fields Find the magnetic field (strength and direction) at position 1, 2, 3. This can also be verified by a simple experiment of keeping a magnetic compass near any current-carrying wire. What is the acceleration ar(t) of the rod? There are different types and shapes of current-carrying conductors. Coincidentally, I was writing an answer with the same argument as yours. B = B j ^. de/ph 14 e/mfwire. Make a circle around the wire taking r as a radius. We know that when electric current flows through the straight current-carrying conductor then it creates a magnetic field that encircles the conductor as shown below: Learn more about magnetic field due to straight current-carrying conductor. d B = 0 4 I d l s i n 90 o r 2. d B = 0 4 I d l r 2. In my edit i used $dl$ with your meaning of $dI$. When B is along the plane of the loop? Step 1: Identify the current {eq}I {/eq} flowing in the wire and distance {eq}r {/eq} from the wire at. Increasing in a direction shown by RH rule B. The current through S 1 is I. Let dl be a small current element at a distance r from P. The greater the current in the wire, or the greater the magnetic field, the faster the wire movement because of the greater force created. What is the value of magnetic field at a point (a, b), if both the conductors carry the same current I? Thus, the magnetic field created by the current-carrying wire is denoted as the ratio of the product of magnetic permeability and current to its distance from the wire. So lets start, So going further, lets recall what Biot-Savart Law states, Biot-Savart Law states that-. A moving charge in a magnetic field experiences a force perpendicular to its own velocity and to the magnetic field. Also, this magnetic field forms concentric circles around the wire. The magnetic field is + ^ -directed for current flowing in the + z direction, so the magnetic field lines form concentric circles perpendicular to and centered on the wire. And now, if we take the cross product we would get $$ d\mathbf{l} \times \mathbf{r} = -z ~dl \hat j + rsin\theta \hat k$$ and therefore the magnitude of dB is equal to $$ dB = \mu_0/4\pi ~I~ |d\mathbf{l} \times \mathbf{r}| /r^3 = \mu_0/4\pi ~I ~ \sqrt{z^2+r^2sin^2\theta} dl/ r^3 $$. There is no conducting current through S 2 The electric flux through S 2 is EA A is the area of the capacitor plates E is the electric field between the plates If q is the charge on the plate at any time, E = EA = q/ o, Example: Capacitor contd The displacement current is the same as the conduction current through S 1 The displacement current on S 2 is the source of the magnetic field on the surface boundary, Magnetic field of a solenoid: Lab results What is the direction of the magnetic field is generated by this solenoid? The direction of this field is perpendicular to the plane of the diagram and is going into it. The direction of magnetic field is given by Right hand thumb Rule Applying Right hand thumb rule, we get magnetic field as It is in form of concentric circles near the current carrying loop (wire) As we move away from wires, the circles become bigger and bigger By the time we reach center of circular loop, the arcs appear as a straight line Lets consider a straight ${I}$ current-carrying conductor of length $l$, on it take a small portion of the conductor ($\displaystyle{dl}$), thus ${I}$ is flowing through the whole conductor then the same current will also flow in that small portion of the conductor, so in this whole article, we will call it as small current element $\displaystyle{Idl}$. how do we know that the magnitude of B is going to be constant and its direction will be the same as a line element. Expert Answer. A. data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAKAAAAB4CAYAAAB1ovlvAAAAAXNSR0IArs4c6QAAAnpJREFUeF7t17Fpw1AARdFv7WJN4EVcawrPJZeeR3u4kiGQkCYJaXxBHLUSPHT/AaHTvu . Would salt mines, lakes or flats be reasonably found in high, snowy elevations? Therefore, we have a small portion of the conductor $\displaystyle{dl}$ then the magnetic field at the point P, due to the current in this small portion of the conductor will be also small i.e $\displaystyle{dB}$. The second term Id is called displacement current and is caused by electric fields that vary with time as in a capacitor. 73 Homework Statement Consider a spiral of 20 turns with inner radius R and outer radius 2R. Solution : For the conductor along the X- axis, the magnetic field, $ \displaystyle B_1 = \frac{\mu_0}{4 \pi} \frac{I }{b} ( sin\theta_2 + sin\frac{\pi}{2} ) $ ; along the negative Z-axis, $ \displaystyle B_1 = \frac{\mu_0}{4 \pi} \frac{I }{b} ( \frac{a}{\sqrt{a^2 + b^2}} + 1 ) $, For the conductor along Y-axis, the magnetic field is, $ \displaystyle B_2 = \frac{\mu_0}{4 \pi} \frac{I }{a} ( sin\theta_1 + sin\frac{\pi}{2} ) $ ; along the negative Z-axis, $ \displaystyle B_2 = \frac{\mu_0}{4 \pi} \frac{I }{a} ( \frac{b}{\sqrt{a^2 + b^2}} + 1 ) $, $ \displaystyle \vec{B} = \vec{B_1} + \vec{B_2} $, $ \displaystyle B = \frac{\mu_0}{4 \pi} \frac{I }{b} ( \frac{a}{\sqrt{a^2 + b^2}} + 1 ) + \frac{\mu_0}{4 \pi} \frac{I }{a} ( \frac{b}{\sqrt{a^2 + b^2}} + 1 ) $, $ \displaystyle B_2 = \frac{\mu_0 I}{4 \pi a b} ( a + b + \sqrt{a^2 + b^2} ) $, Example : A current I is established in a closed loop of an triangle ABC of side l . Find an answer to your question Magnetic field due to current carrying wire derivation Mdamaan1357 Mdamaan1357 . 83 x 10 -16 T k -. To apply Ampere's law to determine the magnetic field within the solenoid, loop 1 encloses no current, and loop 3 encloses a net current of zero. JavaScript is disabled. Magnetic Force Between Two Parallel Conductors, FB Force per unit length: Biot-Savart Law: Field produced by current carrying wires Distance a from long straight wire Centre of a wire loop radius R Centre of a tight Wire Coil with N turns Force between two wires, Numerical Problem What are the magnetic field strength and direction at the dot in the figure? The magnetic field due to current in an infinite straight wire is given by Equations [m0119_eACLLCe] (outside the wire) and [m0119_eACLLCi] (inside the wire). According to Biot-Savarts law, the magnetic induction at P due to the small element is, $\large dB = \frac{\mu_0}{4\pi} \frac{I dl sin\phi}{r^2}$ (i), $\large dB = \frac{\mu_0}{4\pi} \frac{I (a sec^2\theta d\theta) cos\theta}{a^2 sec^2 \theta}$, $\large dB = \frac{\mu_0}{4\pi} \frac{I}{a}cos\theta d\theta $, $\large B = \frac{\mu_0}{4\pi} \frac{I}{a} \int_{-\theta_1}^{\theta_2} cos\theta d\theta $, $\large B = \frac{\mu_0}{4\pi} \frac{I}{a} (sin\theta_1 + sin\theta_2) $, Case I: If the wire extends to infinity on either side of o then, $ \displaystyle B = \frac{\mu_0}{4 \pi} \frac{I }{R} ( sin\frac{\pi}{2} + sin\frac{\pi}{2}) $, $ \displaystyle B = \frac{\mu_0}{4 \pi} \frac{2 I}{R} $, Case II: If length of the wire is finite say L and P lies on right bisector of wire, then, $ \displaystyle \theta_1 = \theta_2 = \theta = sin^{-1}(\frac{L}{\sqrt{4R^2 + L^2}} )$, $ \displaystyle B = \frac{\mu_0}{4 \pi} \frac{ I}{R} (2 sin\theta)$. Could you clarify what confuses you about the integral? Two loops of wire carry the same current of , but flow in opposite directions as seen in Figure 9.4.3.One loop is measured to have a radius of while the other loop has a radius of .. To subscribe to this RSS feed, copy and paste this URL into your RSS reader. = BA Why? Find the ratio of the magnetic field BA at A and BB at B. I forgot that. @Knight I think you are mixing up $d\vec l$ and $d\vec I$. Line Integral Let the sum become an integral: The integral says to divide the line into increments and evaluate the dot product at each one. Magnetic-field on the axis of the circular current-carrying loop. Eddy currents flow in closed loops within conductors, in planes perpendicular to the magnetic field. What is this fallacy: Perfection is impossible, therefore imperfection should be overlooked, If he had met some scary fish, he would immediately return to the surface. Mathematically, it can be denoted as : B = o I 2 r where The more pieces, the better the answer. Why isnt magnetic field at the centre of a circular current-carrying loop zero? We use cookies to ensure that we give you the best experience on our website. When B is perpendicular to the loop? Magnetic Field due to a Current. 2 Important cases If B is everywhere perpendicular to a line, the line integral of B is : = 0 If B is everywhere tangent to a line of length L, and has the same magnitude B at every point, the line integral of B is : = BL. Thus, this article will derive an expression for the magnetic field due to a straight current-carrying conductor. confusion between a half wave and a centre tapped full wave rectifier. rev2022.12.11.43106. Direction of Force Between Two Parallel Conductors If the currents are in the: same direction the wires attract each other. Hebrews 1:3 What is the Relationship Between Jesus and The Word of His Power? So in order to calculate the strength of this magnetic field, Jean Baptiste Biot and Flexis Savart have developed a mathematical equation in the year 1820, which is known as Biot-Savart Law. Ques. There are few laws that apply across every one of the million and more worlds of the Imperium of Man, and those that do are mostly concerned with the duties and responsibilities o Oh, right. The farmer wants to know whether he needs to apply a nitrogen-containing fertilizer to his field. First, we calculate. A. Answer Problem # 14: Find the magnetic field (strength and direction) at position 1, 2, 3 Use B = 0 I/2d B 1 = 6. B = 0 4 I d l r 2. $d\vec I$ is a differential element of current in the straight wire. Let's begin by considering the magnetic field due to the current element I d x I d x located at the position x. Alternatively the information contained in the image may be converted into an electrical signal by scanning and subsequently picked up by a photo- electronic converter. Find the magnitude of the magnetic field a distance of 2 meters from the wire. 67 x 10 -5 T (out) B 2 = 2 x 10 -4 T (in) B 3 = 6. Line Integral The line integral is much like the surface integral only the integration is along a line, not around a surface, hence the name. Net field can be obtained by integrating equation. The force between two parallel current-carrying wires. The direction of the magnetic field is dependent on the direction of the current. Consider a straight conductor carrying current i. Figure 7.8. assemblies offer more structural superiority and functional advantages. Magnetic field due to current-carrying coil. Let P be a point at a perpendicular distance a from the conductor. Well, the magnitude is easy. Furthermore, the direction of the magnetic field depends upon the direction of the current. Why does the USA not have a constitutional court? Your email address will not be published. MathJax reference. As we know, current-carrying conductors experience magnetic fields. Note The overall shape of the magnetic field of the circular loop is similar to the magnetic field of a bar magnet. Debian/Ubuntu - Is there a man page listing all the version codenames/numbers? 1: The magnetic field exerts a force on a current-carrying wire in a direction given by the right hand rule 1 (the same direction as that on the individual moving charges). In a uniform magnetic field, a current-carrying loop of wire, such as a loop in a motor, experiences both forces and torques on the loop. Figure 22.7. Magnetic field due to straight wire carrying current in hindi | derivation| physics class 12th - YouTube support creator athttps://www.paypal.me/4educationUThis video consists. The direction of the current brings an asymmetry in that direction. Moving charges experience a force in a magnetic field. Pick some distance from the wire (r) and create the observation location as a vector. 02 j 2 B = =(u 0 qvsin/4r )(j)X(i) j X i = +k Answer: 2. Can a current carrying loop or wire produces no magnetic field? Mathematica cannot find square roots of some matrices? Use MathJax to format equations. Choose any arbitrary point P in the free space. 1 When we derive the equation of a magnetic field produced by a long straight current-carrying wire, we do something like this: Imagine a wire carrying a constant current I. If we break $\vec B$ into $\hat r$, $\hat \theta$, and $\hat z$ components, then we see that the $\hat z$ component must be zero because the Biot Savart law requires $\vec B$ to be perpendicular to $\vec I$. The field around the magnet generates a magnetic field, and the rotating magnets in a generator produce electricity. For distances inside the wire you only have a fraction of the current that contributes to the magnetic field and the magnetic field has a finite value at a point on the wire itself. opposite directions the wires repel each other. If x is at a very large distance away from the loop. It is conceivable that different parts of the field could provide different types of samples in terms of nitrogen content. 02 j) = (- i - j) B = (u 0 q/4r 2)v(j)X(-i-j) =(u 0 qvsin/4r 2)(j)X(-i-j) But since j X j = 0 -. This magnetic field can deflect the needle of a magnetic compass. Magnetic Field between Two Loops. Add your answer and earn points. Because of its shape, the field inside a solenoid can be very uniform, and also very strong. In this article, we will discuss magnetic field inside a solenoid, solenoid formula, magnetic field due to a current in a solenoid and magnetic field of solenoid formula. Should I give a brutally honest feedback on course evaluations? Line Integral Evaluate the dot product of B and s at each segment. 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According to electromagnetic field theory, a moving charge produces a magnetic field which is proportional to the current, thus a carrying conductor produces magnetic field around it. In the United States, must state courts follow rulings by federal courts of appeals? Moving coil . Note that there is an involved follow-up part that will be shown once you have found the answer to Part B. Magnetic Field due to a Straight Current Carrying Wire of Infinite Length Since, the length of the wire is infinite, hence the ends x and y are at infinite distance. Therefore, the internal angle made by them at point P would be 1 = 2 = 2 2 Therefore, from equation (7) magnetic field due to a straight current carrying wire of infinite length, We know that the magnitude is constant by symmetry. Magnetic Field between Two Loops Two loops of wire carry the same current of 10 mA, but flow in opposite directions as seen in Figure 12.13. Thanks for contributing an answer to Physics Stack Exchange! Compared with the intensively investigated mononuclear Ln-complexes, polymetallic lanthanide supramol. Figure 11.16 shows a rectangular loop of wire that carries a current I and has sides of lengths a and b. A pair of long, straight current-carrying wires and four marked points are shown in above figure. Magnetic field of a solenoid Is the magnetic field of the top solenoid, in the same direction as the bottom one or opposite? Thus, magnetic field is depending on $r, \theta, z$ . . Magnetic field due to infinite current carrying wire in the X and Y axes Last Post Nov 23, 2020 Replies 11 Views 981 Electric field due to a straight rod Last Post May 6, 2020 Replies 1 Views 346 Electric field due to a ring Last Post Mar 3, 2022 Replies 11 Views 459 Forums Homework Help Introductory Physics Homework Help 02 m, = 1350 B = (u 0/4)(qvsin/r 2) Answer: 2. A magnetic field is a vector field that describes the magnetic influence on moving electric charges, electric currents, [1] : ch1 [2] and magnetic materials. Current in the Wire No Current in the Wire, Magnetic Fields of Long Current-Carrying Wires B = o I 2 r I = current through the wire (Amps) r = distance from the wire (m) o = permeability of free space = 4 x 10 -7 T m / A B = magnetic field strength (Tesla) I, Magnetic Field of a Current Carrying Wire http: //www. Note that within the closed path of loop 3 the currents into the screen cancel the current out of the screen (here the screen means your computer screen or smart phone's). we all know that a current-carrying conductor generates a magnetic field around itself, and we can experience that magnetic field by moving another charge around it, as we know a current-carrying conductor exerts a force on the moving charge and it is calculated by the equation F= qv x b. You will use the ideas of magnetic flux and the EMF due to change of flux through a loop. Can you elaborate your answer just a little? It is certainly different from the magnetic flux density. And its magnitude is determined by the integral you posted. It may not display this or other websites correctly. They carry steady equal currents flowing out of the plane of the paper, as shown in figure. Hans Christian Oersted in 1820s showed that a current carrying wire deflects a compass. (Express your answer as a vector.) Cyclotron (Theory, Diagram and Derivation) Velocity selector. Share Cite Improve this answer Follow It is very helpful in the calculation of the magnetic field at any arbitrary point P, which lies at a distance r from the current-carrying conductor. A charge produces an electric field and also interacts with that field. I think it's this assumption that has really solved the problem and not the mathematics . Integration of magnetic field around a wire Bwire = (u 0 I)/2d (you knew that!) $$ d\mathbf{B} = \mu_0 /4\pi ~ I ~ \frac {d\mathbf{l} \times \mathbf{r}} {r^3} $$ Show with the help of a diagram how the magnetic field due to the current I1 exerts a magnetic force on the second wire. Hence, the magnetic field at point P due to the total length of the conductor is given as-\begin{align*}B&=-\frac{\mu_0 \mu_r I}{4\pi D}\int_{\theta_1}^{\theta_2}{sin\theta d\theta}\\&=-\frac{\mu_0 \mu_r I}{4\pi D}\left[-cos\theta\right]_{\theta_1}^{\theta_2}\\&=\frac{\mu_0 \mu_r I}{4\pi D}\left[cos\theta_1-cos\theta_2\right]\end{align*}, If the length of the conductor is infinitely long then will varies from 0 to that is $\theta_1=0$ and $\theta_2=\pi$, after substituting this value in the final expression of magnetic field, we get-\begin{align*}B&=\frac{\mu_0 \mu_r I}{4\pi D}\left[cos 0-cos\pi\right]\\&=\frac{\mu_0 \mu_r I}{4\pi D}\left[1-(-1)\right]=\frac{2\mu_0 \mu_r I}{4\pi D}\\&=\frac{\mu_0 \mu_r I}{2\pi D}\end{align*}. Magnetic field of a solenoid What is the equation for the magnetic field due to an ideal solenoid? Material: Iron filings Apparatus: Cardboard, thick insulated copper, 4 plotting compasses, low voltage high current d.c. power supply, connecting wires Method: Magnetic field due to straight conductor carrying current - QuantumStudy Magnetic field due to straight conductor carrying current Consider a straight conductor carrying current 'i'. Since, r can be written as $ \mathbf{r} = (rcos\theta, rsin\theta , z) $ and dl as $ d\mathbf{l} = ( dl,0,0) $ The electric potential V at a point in the electric field of a point charge is the work done W per unit positive charge q in bringing a small test charge from infinity to that point, V = W q. Take a point at a distance of r from the wire, this is the point where we want to find the magnetic field. So this is the required derivation for the magnetic field due to a straight current-carrying conductor of finite and infinite length. In magnetics, to calculate the magnetic field of a highly symmetric configuration carrying a steady current, we use Ampere's Circuital Law. Ampere's circuital law. It is given as B = 0 2 I r, where B is the magnitude of the magnetic field measured in teslas T, 0 is the permeability of free space given by a value of 4 10 7 H m where H denotes henrys, I need to fix that part. It only takes a minute to sign up. Magnetic field of a solenoid What is the equation for the magnetic field due to an ideal solenoid (can be derived from Amperes Law)? Constant C. Decreasing in a direction shown by RH rule. This is called Amperes Law. @aditya_stack Okay, but it doesn't make any difference if we take the wire in $x$ direction or $z$ direction, all it gonna change is to swap the components in cross product. The way to set it up would be as an integral over [itex]z[/itex], say, along the wire, with each wire element [itex]dz[/itex] contributing to the field at P based on the distance to point P and the angle between the radius vector and the z-axis. Force on a circular current-carrying loop near a long wire, Trying to visually understand Ampere's Law, Calculating the magnetic field around a current-carrying wire of arbitrary length using Maxwell's Equations, Magnetic field due to a finite-length straight wire carrying a constant current. When would I give a checkpoint to my D&D party that they can return to if they die? B = 0 4 I r 2 d l. Mark a point P at the distance r perpendicular to the conductor. Let 'dl' be a small current element at a distance 'r' from 'P'. Derivation of magnetic field caused by a current carrying wire, Help us identify new roles for community members. Example: Capacitor Consider surfaces S 1 and S 2. Eddy currents (also called Foucault's currents) are loops of electrical current induced within conductors by a changing magnetic field in the conductor according to Faraday's law of induction or by the relative motion of a conductor in a magnetic field. Furthermore, the formation of a magnetic field takes place when a wire carries an electric current. Points A and B are in the plane of the wires. For a solenoid of length L with current I: B = u 0 NI/L. Power factor class 12 definition, and formula. So only the $\hat \theta$ component can be nonzero. Why is the federal judiciary of the United States divided into circuits? Is it appropriate to ignore emails from a student asking obvious questions? A steady current (I1) flows through a long straight wire. Physics Stack Exchange is a question and answer site for active researchers, academics and students of physics. The magnetic field due to each wire at the desired point is calculated. The Biot-Savart law states that- the value of the magnetic field at a specific point in space from one short segment of current-carrying conductor is directly proportional to the current element (short segment of current) and to the sine angle (angle between the current direction and vector position of the point), it is also inversely proportional to the square of the distance of the point from the current element Idl. document.getElementById("ak_js_1").setAttribute("value",(new Date()).getTime()); Laws Of Nature is a top digital learning platform for the coming generations. Hans Christian Oersted in 1820's showed that a current carrying wire deflects a compass. However, before we discuss the force exerted on a current by a magnetic field, we first examine the magnetic field generated by an electric current. The distance from the first loop to the point where the magnetic field is measured is , and the distance from that point to the second loop is . Next, the direction of each magnetic field's contribution is determined by drawing a circle centered at the point of the wire and out toward the desired point. Asking for help, clarification, or responding to other answers. Right, along the length of the solenoid B. left, along the length of the solenoid C. 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